Question

031. An element is placed in the second group and third period of the periodic table and
in presence of Oxygen forms a basic oxide. (3)
(i) Identify the element and write its electronic configuration
(it) Write a balanced chemical equation when it burns in the presence of air.
(ii) Draw the electron dot structure for the formation of this oxide.​

Answer 1

Answer:

I) Potassium (K) [Ne]3s^2 or 1s^1 2s^2 2p^6 3s^2

II) 2K + O2 ----> 2KO

III) K:ö::ö:K