Question

04. A particle moves along a straight line such that its by t=ra is given timo any positional s=(t3-6t2-3t+4) metres. The velocity when the acceleration is zero is
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Answer 1

Explanation:

Correct option is

D

−9 m/s

S=t

3

−6

2

+3t+4

v=

dt

ds

So =3t

2

−12+3=v

again differentiate ,a=

dt

dv

6t−12=0

t=2s

v=3(2)

2

−12×2+3=−9ms

−1

Hence (D) is correct answer.

Answer 2

Answer is -15 m/s.

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