Question

04.
angle.
In a quadrilateral, CO and DO are the interior bisector of angle C and angle D respectively.
Prove angleA + angle B = 2 angle COD​

Answer 1

Answer:

In △COD,

∠COD+∠1+∠2=180

o

∠COD=180

o

−(∠1+∠2)

∠COD=180

o

−

2

1

​

(∠C+∠D)

∠COD=180

o

−

2

1

​

[360

o

−(∠A+∠B)]

∠COD=

2

1

​

(∠A+∠B)

Step-by-step explanation: