Question

04
from what value of k do the quations are 11 BO
and 6x -ky 18 depresent Cornelikents lines?​

Answer 1

Answer:

which subject

regards

brainly staff

Answer 2

Answer:

Correct option is

A

solution of 3

k

−9=0

C

2

Given equations are 3x−y+8=0 and 6x−ky=−16

For coincident lines,

6

3

=

−k

−1

⇒

2

1

=

k

1

⇒k=2

For option A:

3

k

−9=3

2

−9=0

which satisfies R.H.S.

Now for option B:

2

k

−8=2

2

−8=4−8=−4

which does not satisfies R.H.S.

Hence, options A and C are correct.