Question

04- In a group of athletic teams in a school, 21 are in basketball team, 26 in hockey team, 29 in
football team. If 14 play hockey team,29 in football team. If 14 play hockey and basketball, 12
play football and basketball, 15 play hockey and football and 8 play all the three games. Find
(1)- how many players are there in all.
(il) how many play football only.
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Answer 1

Step-by-step explanation:

Given In a group of athletic teams in a school, 21 are in basketball team, 26 in hockey team, 29 in football team. If 14 play hockey team,29 in football team. If 14 play hockey and basketball, 12

play football and basketball, 15 play hockey and football and 8 play all the three games. Find

(1)- how many players are there in all.

(il) how many play football only.

• Let h be the members in hockey team, b be the member in basket ball team and f be the member in football team.
• So n(b) = 21, n(h) = 26, n(f) = 29
• 14 play both hockey and Basketball
• So n (h Ո b) = 14
• 15 play hockey and football
• So n (h Ո f) = 15
• 12 play football and basketball
• So n(f Ո b) = 12
• Now 8 play all the 3 games.
• So n (h Ո b Ո f) = 8
• Now we have  
• So n(h U b U f) = n(h) + n(b) + n(f) – n(h Ո b) – n(h Ո f) – n(f Ո b) + n(h Ո b Ո f)
•                          = 21 + 26 + 29 – 14 – 15 – 12 + 8  
•                          = 43
• Also we can do as by drawing a Venn diagram,
• Total number of players will be 5 + 7 + 6 + 8 + 4 + 3 + 10 = 43

Reference link will be

https://brainly.in/question/21521563

Answer 2

Answer:

11) 10 play only football....