Question

04
Solve.
609
А
(1) is the centre and PB is a
diameter of the circle. BC is the
tangant of the circle with Bas
point of contact. If ZAPB = 60°
then marc AQB) = ?
(i) (mm) 2 PBA = ?
B
С
(iv) marc APB) = ?

Answer 1

Answer:

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