Question

04. The combustion products of H₂S and SO₂ gas are information on reactions below. H₂ (g) + S (s) → H₂S (g) Δ H = -21 KJ S (s) + O₂ (g) → SO₂ (g) Δ H = -297 K H₂ (g) + 1/2O 2 (g) ) → H₂O (g) Δ H = -242 KJ it is concluded that the energy given off in the combustion of 1 mole of H₂S (g) from the equation is: H₂ (g) + 1 / 2O₂ (g) → SO₂ (g ) + H2O (g) ΔH =? *

a) - 67 Kj
b) + 34 Kj
c) - 560 Kj
d) -34 Kj
e) - 518 Kj

Help, pls

Answer 1

Chemistry

Calculate ΔH

o

for the reaction,

Na

2

O(s)+SO

3

(g)→Na

2

SO

4

(g) using the following :

Na(s)+H

2

O(l)→NaOH(s)+

2

1

H

2

(g);ΔH

o

=−146kJ

Na

2

SO

4

(s)+H

2

O(l)→2NaOH(s)+SO

3

(g);ΔH

o

=+418kJ

2NaO(s)+2H

2

(g)→4Na(s)+2H

2

O(l);ΔH

o

=+259kJ