Question

05 Find the perimeter of the following Rectangle
i Length = 18 cm, Breadth = 10 cm​

Answer 1

Answer:

Step-by-step explanation:

2 ( l + b)

2 * 28

56cm = perimeter

Answer 2

Question :-

• Find the perimeter of the following Rectangle whose Length = 18 cm, Breadth = 10 cm

Answer

Given :-

• Length of the rectangle = 18 cm

• Breadth of the rectangle = 10 cm

We know,

• Perimeter of rectangle is given by

$\boxed{ \green{ \bf \: Perimeter_{(rectangle)}=2(Length×Breadth)}}$

Therefore,

$\rm :\implies\:Perimeter_{(rectangle)} \: = \: 2 \times (18 + 10)$

$\rm :\implies\:Perimeter_{(rectangle)} = 2 \times 28$

$\boxed{ \pink{ \bf \: \implies \: Perimeter_{(rectangle)} = 56 \: cm}}$

Additional Information :-

Perimeter of rectangle = 2(length× breadth)

Diagonal of rectangle = √(length ²+breadth ²)

Area of square = side²

Perimeter of square = 4× side

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²