Question

05.
If sino + coso = m then value of (sino - Cose) is​

Answer 1

Answer:

Step-by-step explanation:

Sinθ + Cosθ = m.

//Square on both sides

=> (Sinθ + Cosθ)² = m²

=> Sin²θ + Cos²θ + 2SinθCosθ = m²

=> 1 + 2SinθCosθ = m²

=> 2SinθCosθ = m² - 1

=> SinθCosθ = 1/2(m² - 1)

Now to find value of Sinθ - Cosθ

(Sinθ - Cosθ)² =  Sin²θ + Cos²θ - 2SinθCosθ

=> (Sinθ - Cosθ)² = 1 - 2 * 1/2(m² -1 )

=> (Sinθ - Cosθ)² = 1 - m² + 1

=> (Sinθ - Cosθ)²  = 2 - m²

=> Sinθ - Cosθ = ±√(2 - m²).