05) Under the action of a force, a block of mass 2
kg is moved in such a way that it's position is given
+3
by x= metre. What is the work done by the force
3
in the first 2 sec?
A) 123
C) 20J
B) 8J
D) 16J
Answers
Answer:
Work done by the force is .
Explanation:
It is given that,
Mass of the object, m = 2 kg
Its position as a function of time t is given by :
Velocity,
Where
x is in meters
t is in seconds
We need to find the work done by the force in first two seconds. The work done by an object is given by :
................(1)
Where
v is the final velocity
u is the initial velocity
At t = 0, u = 0
At t = 2 s,
Put the values of u and v in equation (1), we get :
So, the work done by the force in first two seconds is . Hence, this is the required solution.
Answer:
Explanation:
Under the action of a force, a 2kg body moves such that its position x as a function of time is given by x=
3
3
where x is in metre and t in second. The work done by the force in the first 2 s is :