Question

05. When a current of 0.5A is drawn
in a battery, then the potential
difference drops to 16 V. Determine the
emf and Internal resistance of battery​

Answer 1

Answer:

32

Explanation:

V÷I=R

160÷5=R

32

Resistance is 32

Answer 2

Given :-

Current of the battery = 0.5 A

Voltage of the battery = 16 V

To Find :-

The e.m.f. and Internal resistance of battery​.

Analysis :-

Here we are given with the current and voltage of the battery.

In order to find the resistance of the battery substitute the values given in the question using the formula of voltage.

Solution :-

We know that,

• i = Current
• v = Voltage
• r = Resistance

Using the formula,

$\underline{\boxed{\sf Voltage=Current \times Resistance}}$

Given that,

Voltage (v) = 16 V

Current (i) = 0.5 A

Substituting their values,

⇒ V = IR

⇒ 16 = 0.5 × R

⇒ R = V/I

⇒ R = 16/0.5

⇒ R = 32 Ω

Therefore, the resistance of the battery is 32 Ω.