Question

06. Aspherical ball of radius 3 cm is melted and the recast into three spherical balls. If the radil of two of
these balls are 1.5 and 2cm, then the radius of the third ball is
* 10.5cm
b)1 cm
415 cm
d) 2.5 cm​

Answer 1

Answer:

here is your answer and once try to solve it yourself

Answer 2

Answer:

(d) 2.5 cm

Step-by-step explanation:

Volume of the large spherical ball

= 4/3 × π × r³ = 4π/3 × 3 × 3× 3

= 4π × 9 = 36π cm³

Volume of all the spheres = volume of original sphere

= 4π/3 × r1³ + 4π/3 × r2³ + 4π/3 × r3³ = 36π

= 4π/3[r1³ + r2³ + r3³] = 36π

= 1/3[(1.5)³ + (2)³ + r3³] = 9

= [3.375 + 8 + r³] = 27

=》 11.375 + r³ = 27 =》 r³ = 15.625

=》 r = ³√15.625 =》 r = 2.5 cm

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