Question

06. Find the area of a tringle two sides of which are 18 cm and 10 cm and the perimeter is
42 cm
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Answer 1

Answer:

area of the triangle is 21√11

Step-by-step explanation:

a= 18 cm

b= 10 cm

perimeter= 42 cm

semi perimeter 's'= perimeter/2

s = 42/2

s = 21 cm

s = a+b+c/2

21 = 18+10+c/2

21 = 28 +c/2

21×2 = 28 + c

42-28 = c

c = 14

area of a triangle = √s(s-a)(s-b)(s-c)

= √21(21-18)(21-10)(21-14)

= √21×3×11×7

= √7×3×3×11×7

= 7× 3 √11

= 21√11

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