07. The 6th term of an AP is - 10 and its 10th term is - 26. Determine the 15th term of the Ap.
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Answered by
4
Step-by-step explanation:
t6 => a + 5d = -10
t10 => a + 9d = -26
By solving the equations,
d = -4
a = 10
t15 = a + 14d
= 10 - 56
= -46
Answered by
14
T6 = a + 5d = -10 --(1)
T10 = a + 9d = -26 ---(2)
From eq(1) and eq(2)
-4d = 16
d = -16/4
d = -4
a = -10 - 5d
a = -10 - 5 × -4
a = -10 +20
a = 10
T15 = a + 14d
T15 = 10 + 14 ×(-4)
T15 = 10 + (-56)
T15 = 10 - 56
T15 = - 46 ans.
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