Question

07.
The area of a square field is 60025m-.A man cycles along its boundary at 18 km
per hour. In how much time will he return to the starting point?​

Answer 1

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Answer 2

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$The \ area\ of \ a \ square \ field \ is \ 60025 \ m^2. \\ A\ man \ cycles \ along\ its\ boundary \ at \\ 18 km h^{-1}. \ In\ how\ \ much\ time\ will\ he\\ return\ to\ the\ \ starting \ point$

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$\boxed{\red{\bold{Given:}}}$

$\red{\implies}Area\ of \ square \ field = 60025 m^2$

$\red{\implies}Side \ of \ field = \sqrt{Area}$

$\red{\implies}Side \ of \ field = \sqrt{60025 m^2}$

$\red{\implies}Side \ of \ field = 245 m$

$\boxed{\red{\bold{Perimeter:}}}$

$\blue{\implies}Perimeter = 4 × side$

$\blue{\implies}Perimeter = 4 × 245 m$

$\blue{\implies}Perimeter = 980 m$

$\purple{\implies}Speed = 18 km/hr$

$\purple{\implies}Speed = 18 × \displaystyle\frac{1000}{3600} m s^{-1}$

$\purple{\implies}Speed = 5 \ ms^{-1}$

$\boxed{\red{\bold{Hence :}}}$

$\green{\implies} The \ time \ to \ take \ a \ round = \displaystyle\frac{Distance}{Speed}$

$\green{\implies}\therefore Time \ taken = \displaystyle\frac{980}{5}$

$\green{\implies}Time \ taken = 196 s$

$\green{\boxed{\implies{\boxed{Time \ taken = 3 \ min \ 16 \ sec}}}}$

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