Question

07. The Laplace transform of x(t)=u(t+2)+u(t-2) is

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Answer 1

Answer:

X(s)e±st0

L{u(t-2)}=e−2ss; L{u(t+2)}=e2ss

∴X(s) = L{u(t+2)+u(t-2)} = e−2s+e−2ss=cosh2ss

Answer 2

The Laplace transform was invented by Pierre Simon Laplace which was named after him.

It is an integral transform.

It converts a function of real variable into a function of a complex variable.

It is useful in solving  linear ordinary differential equations.

Hence,the Laplace transform of X(s)=L{u(t+2)+u(t-2)} is

X(s) = L{u(t+2)+u(t-2)} =

= $\frac{e^{-2s}+e^{-2s}}{s}$

=$\frac{cosh2s}{s}$

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