Geography, asked by ItzKajukiBarfi, 16 days ago

08. A jet plane starts from rest with an acceleration of 3ms-2 and makes a run for 35s before taking off. What is the minimum length of the runway and what is the velocity of the jet at take off?.

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Answers

Answered by suyashshirsath182007
0

Answer: Given: u= 0m/s

a=3m/s-2

t=35s

s=?

v=?

Explanation: s=ut+1/2*a*t2

=0*35+1/2*3*1225

=0+3*612.5

=1837.5

Therefore, distance or the minimum length of runway is 1837.5 meters

Now, v=u+at

=0+3*35

=105m/s

Therefore, the velocity of the jet to take off is 105m/s.

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