Question

08. Factorise 1 + 64x³​

Answer 1

Step-by-step explanation:

We know,

(a3+b3)=a3+a2b−a2b−ab2+ab2+b3

                  =(a3+a2b)−(a2b+ab2)+(ab2+b3)

                  =a2(a+b)−ab(a+b)+b2(a+b)

                  =(a+b)(a2−ab+b2)

Now, given, 1+64x3

      =13+(4x)3

      =(1+4x)(1−4x(1)+(4x2))

      =(1+4x)(1−4x+16x2)

Answer 2

Answer:

64x^3 + 1

》( 4x )^3 + ( 1 )^3

According to the identity ,

( a + b )^3 = ( a + b )( a^2 + ab + b^2 )

》( 4x + 1 )[ ( 4x )^2 - ( 4x )( 1 ) + ( 1 )^2 ]

》( 4x + 1 )( 16x^2 - 4x + 1 )