Question

08. Find the values of a and b so that the polynomials P(x) and Q(x) have (x2-5x-12)
as their HCF, where
P(x) = (x2 - 5x + 4) (x2 + 5x + a)
Q(x) = (22 + 5x + 6) (22 – 5x – 26)​

Answer 1

Answer:

HCF become LCM CHF become HCF so LCM is single no answer sorry for this only for points please I am sorry