08
If
ax'+boc tc =0 equal, then the
Value
the goots of
of
aaat ba +6=0
Answers
Answered by
1
Answer:
Correct option is
B
have negative real parts
Since, a,b,c>0 and ax
2
+bx+c=0 then,
⇒ x=
2a
−b
±
2a
b
2
−4ac
Case1: When b
2
−4ac>0
⇒ x=
2a
−b
−
2a
b
2
−4ac
and
2a
−b
+
2a
b
2
−4ac
both roots are negative.
Case2: Ehen b
2
−4ac=0
⇒ x=
2a
−b
i.e., both roots are equal and negative.
Case3: When b
2
−4ac<0
⇒ x=
2a
−b
±i
2a
4ac−b
2
have negative real part.
∴ From above discission both roots have negative real parts.
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