Question

08. Two cross roads each of width 5m run right angles through the centre of a
rectangular park of length 80 m and breadth 40m and parallel to the sides.
Find the area of the roads.​

Answer 1

Answer:

Answer

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm