Question

08. What is the minimum length of the runway and what is the velocity of the jet at take off?
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hello property owner xD ^_^
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Answer 1

Explanation:

mc, bc

Produce CD to cut AB at E.

Produce CD to cut AB at E.Now, ΔBDE, we have

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBE

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o Put in (1)

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o Put in (1)x=78+40=118

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o Put in (1)x=78+40=118 o

Produce CD to cut AB at E.Now, ΔBDE, we have∠CDB =∠CEB+∠DBEx=∠CEB+40 ………..(1)In ΔAEC∠CEB=∠CAB+∠ACE∠ CEB =48+30=78 o Put in (1)x=78+40=118 o .