Question

09
26. Two trains A and B, 100 km apart are travelling towards each other with
starting speed of 50 km hr" for both. The train A is accelerating at 18 km hr- and
the train B is deaccelerating at 18 km hr-2. The distance where the engines cross each
other from starting point of A is​

Answer 1

initial relative displacement = 100

final relative displacement = 0

relative speed initially = 50×2 = 100

relative acceleration= 18-18 = 0

s= ut + 1/2. at^2

100 = 100t

t= 1

So they meet after 1s

from A we have to find

so its distance travelled by A

= ut +1/2 at^2 = 50 + 1/2 18 = 50+9 = 59km