Question

09 - A body starts with an initial velocity of 10m per sec - 1 and accelerates with 5m per second- 2. Find the distance covered by it in 5 second​

Answer 1

Given:-

• Initial velocity,u = 10 m/s

• Acceleration,a = 5 m/s²

• Time taken,t = 5 s

To be calculated:-

Calculate the distance covered by a body.

Formula used:-

s = ut + 1/2 at²

Solution:-

From the second equation of motion,

s = ut + 1/2 at²

★ Putting the values in the above formula,we get:

s = 10 × 5 + 1/2 × 5 × ( 5 )²

s = 50 + 1/2 × 5 × 25

s = 50 + 1/2 × 125

s = 50 + 62.5

s = 112.5 m

Thus,the distance covered by a body is 112.5 m.

Additional information:-

• v = u + at

• v² = u² + 2as

Answer 2

$\huge\underline{\purple{ANSWER:-}}$

$\bigstar$ CONCEPTS:-

✔️When body moves with constant acceleration,

• $\longrightarrow\rm{\vec{v}\:=\:\vec{u}\:+\:\vec{a}t}$
• $\longrightarrow\rm{\vec{s}\:=\:\vec{u}\:t\:+\:\dfrac{1}{2}\:\vec{a}}$t²

Where,

☞ v = final Velocity

☞ u = initial Velocity

☞ a = acceleration

☞ t = time

☞ s = distance

SOLUTION:-

${\bold{\red{\underline{Given}-}}}$

• initial Velocity (u) = 10m/s
• acceleration (a) = 5 m/s²
• time (t) = 5 second

☞So, we have know that

• s = ut + 1/2 at²

✔️=> s = 10×5 + 1/2 ×5×5²

✔️ => s = 50 + 62.5

✔️ => s = 112.5 m

$\bigstar\:\underline{\boxed{\bf{\red{Required\: Answer\:=\:112.5\:meter}}}}$