Question

09
-
civen :-
AB and co intrect ato
LAOC + BOE = 10 & BOD 10
Eind -
BOE & reflex / LOF​

Answer 1

Answer:

$We have,</p><p>∠BOD=40∘</p><p></p><p></p><p>⇒∠AOC=40∘     [∵∠AOC=∠BOD (vertically opposite angles)]</p><p></p><p></p><p>Now, ∠AOC+∠BOE=70∘</p><p></p><p></p><p>⇒40∘+∠BOE=70∘⇒∠BOE=30∘</p><p></p><p>$

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

o r (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

 

Plz mrk as brainliest ❤