09. Find the smallest number which when divided by 15 leaves remainder 5. when divided
by 5 remainder 15, when divided by 35 leaves remainder 25.
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Answer:
The LCM of the numbers 15, 25 and 35 will be 75∗7=525
Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15. In each case, we are 10 short of getting a zero remainder. So the desired number must be 525−10=515
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