Question

09:- Find the Zeroes of the polynomial
6x²-7x-3​

Answer 1

6x²-7x - 3

to find the zeroes of the polynomial,

6x²-7x - 3 = 0

6x²-9x +2x -3 = 0

3x(2x-3) + 1(2x -3) = 0

(3x+1) (2x-3) = 0

x = -1/3 or 3/2

Answer 2

Answer:-

$\purple{\bigstar}$ Zeroes of the polynomial are

$\large\leadsto\boxed{\rm\blue{x = \dfrac{3}{2}}}$

$\large\leadsto\boxed{\rm\blue{x = \dfrac{-1}{3}}}$

• Given:-

✧ $\sf{6x^2 - 7x - 3}$

• To Find:-

Zeroes of the polynomial

• Solution:-

✧ $\sf{6x^2 - 7x - 3}$

Splitting the middle term:-

→ $\sf{6x^2 - 9x + 2x - 3}$

→ $\sf{3x(2x - 3) + 1(2x - 3)}$

→ $\sf{(2x - 3)(3x + 1)}$

Now,

✧ $\sf{(2x - 3)}$

→ $\sf{2x - 3 = 0}$

→ $\sf{2x = 3}$

→ $\boxed{\bf\red{x = \dfrac{3}{2}}}$

Also,

✧ $\sf{(3x + 1)}$

→ $\sf{3x + 1 = 0}$

→ $\sf{3x = -1}$

→ $\boxed{\bf\red{x = \dfrac{-1}{3}}}$

Therefore, the zeroes of the given polynomial are:-

$\pink{\bigstar}$ $\bf{x = \dfrac{3}{2}}$

$\pink{\bigstar}$ $\bf{x = \dfrac{-1}{3}}$