Question

09. If 15 boys working independently and at the same rate can assemble 30 machines in an
hour, How many machines would 48 boys working independently and at the same rate
assemble in 40 minutes?
54
b. 64
C. 96
d. 68​

Answer 1

15 boys = 30 machines

Therefore, 1 boy = 30/15 = 2 machines

Therefore, 48 boys = 48×2 = 96 machines

The correct option is C(96).

Answer 2

Answer:

The correct answer is Option(B) 64.

Step-by-step explanation:

15 boys take 1 hour to assemble 30 machines.

Logically,

$\frac{15}{30}$ boys take 1 hour to assemble $\frac{30}{30}$ machines

1 boy will take 1 hour to assemble 2 machines

Therefore 48 boys will take one hour to assemble 96 machines.

1 hour = 60 minutes

1 minute = 1/60 hour

40 minutes = 40/ 60 hours

40 minutes = 2 / 3 hour

48 boys will take 2/3 hours to assemble 2/3x96 machines.

Therefore, 48 boys will take 40 minutes to assemble 64 machines.

48 boys working independently and at the same rate will assemble 64 machines in 40 minutes.

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