Question

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09. Sᴏʟᴠᴇ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ:
1. Sᴜʙᴛʀᴀᴄᴛ 2ᴀ -3ʙ - ᴄ ғʀᴏᴍ ᴀ – 4ʙ - 6ᴄ
2. Iғ A = ᴀ + ʙ +ᴄ, B = ᴀ - ʙ + ᴄ ᴀɴᴅ
C = ᴀ-ʙ-ᴄ. Fɪɴᴅ A+B- C?
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Answer 1

❏ Question:-

★ Subtract 2A-3B-C From A-4B-6C

★ Iғ A = a + b +ᴄ, B = a - b + ᴄ ᴀɴᴅ

C = a-b-ᴄ. Fɪɴᴅ A+B- C?

❏ Answer:-

Case (1):-

( Subtract 2A-3B-C From A-4B-6C )

➥ (2A-3B-C)-(A-4B-6C)

➥(2A-A-3B+4B-C+6C)

➥(A+B+5C) [Ans.]

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Case(2):-

Iғ A = a + b +ᴄ, B = a - b + ᴄ ᴀɴᴅ

C = a-b-ᴄ. Fɪɴᴅ A+B- C ?

➥A+B-C=(a+b+c)+(a-b+c)-(a-b-c)

➥A+B-C=(a+a-a)+(b-b+b)+(c+c+c)

➥A+B-C=a+b+3c [Ans.]

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$\boxed{</p><p>\begin{minipage}{7 cm}</p><p></p><p>BODMOS RULE \\ \\</p><p></p><p> \star(+)\times(+)=(+) \\ \\</p><p>\star (-)\times(-)=(+) \\ \\ </p><p>\star (-)\times(+)=(-) \\ \\</p><p>\star(+)\times(-)=(-) \\ \\ </p><p></p><p>\end{minipage}}$

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Answer 2

1. Solution :-

= A-4B-6C -(2A -3B -C)

= A - 4B -6C - 2A + 3B + C

= -A - B - 5C

2. Solution :-

Given :-

A = a + b + c

B = a - b + c

C = a - b - c

Now,

= A + B - C

= (a + b + c) + (a - b + c) - (a - b - c)

= a + b + c + a - b + c - a + b + c

= a + b + 3c