09
Use division algorithm to show that the square of any positive integer is ofthe form
3p or 3p+1.
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Let the positive integer-a
b-3
If b - 3 so
0</= R < b
R =0, 1,2
q= some integer
By using division algorithm
let r =0
a=bq+r
a =3q + 0
a=3q
squaring both side
a^ =(3q) ^
a^= 9q^
a^=3(3q^)
let P= 3q^
a^ = 3P ____________1
Let r = 1
a=bq+ r
a= 3q + 1
squaring both side
a^= (3q+1) ^
a^=(3q)^ + (1) ^ + 2 ×3q×1
a^ =9q^ +1+6q
a^= 9q^+6q+1
a^=3(3q^+2q) +1
let 3q^+2q = P
a^=3p+1________________2
From eq 1 and 2 we can say that the square of any positive integer is in the form of 3q and 3q+1 .
But if you are a cbse student ,then you must know that this part is removed from exam point of view.
Thankyou
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