Question

095
7) A car distributor in city Y experiences on an average 2.5 car sales per day. Find the probability that on a
randomly selected day, they will sell 5 car.
nnossa​

Answer 1

Answer:

12.5

Step-by-step explanation:

2.5 x5=12.5

I DONT KNOW IF IM RIGHT

Answer 2

Given:  average 2.5 car sales per day

To find: probability on a randomly selected day

Find:

We can find the solution using Poisson Solution

Let us take

x = 5 cars on random day

e= 2.71828

λ= lamda= 2.5 cars/day

Substitute these terms in the Poisson distribution formula

P(x)= λˣe⁻¹ / x!

P(x)=  2.5⁵ e⁻²°⁵/ 5!

After solving

2.5⁵ = 97.65625

e⁻²°⁵= 2.71828⁻²°⁵

       = 0.08208

5!= 5x4x3x2x1

   = 120

Substituting the values

P(x)= (97.65625 x 0.08208)/ 120

     = 8.015626/120

    = 0.06679

The probability that on a randomly selected day, they will sell 5 cars is 0.06679