Question

0lzz give detail answer

Answer 1

Let the mass of H2 , O2 and CH4(methane) be x grams

• x grams of H2 --> (x/2) moles of H2
= (22.4/2)x litres
= 11.2 x L

• x grams of O2 --> (x/32) moles of O2
= (22.4/32)x litres
= (11.2/16)x L

• x grams of CH4 --> (x/16) moles of CH4
= (22.4/16)x litres
= (11.2/8)x L
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The ratio of volume of the gases :
= H2 : O2 : CH4
= 11.2 x : (11.2/16)x : (11.2/8)x
= 1 : (1/16) : (1/8)
= 16 : 1 : 2
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Answer 2

Explanation:

The three most common methods are basin irrigation, border irrigation and furrow irrigation. Water is typically introduced at the highest point or along the edge of a field, which allows covering the field by overland flow.