Question

＼(°o°)／

If x = 5 - 2√6

Then find the value of
√x + 1/√x

[Press on the picture for proper question]​

Answer 1

Step-by-step explanation:

$x = 5 - 2 \sqrt{6 } \\ \\ 1 \div x = 1 \div 5 - 2 \sqrt{6}$

multiply and divide by 5+2√6

$1 \div x = (1 \div 5 - 2 \sqrt{6} ) \times ( 5 + 2 \sqrt{6} \div 5 + 2 \sqrt{6} )$

Denominators are like (a+b)(a-b) . So a^2 - b^2

$1 \div x =( 5 + 2 \sqrt{6} ) \div (5 {}^{2} - (2 \sqrt{6} ) { }^{2}$

$1 \div x =( 5 + 2 \sqrt{6} ) \div 1$

now 1/X = 5+2√6

X = 5-2√6

$x + 1 \div x = 5 + 2 \sqrt{6} + 5 - 2 \sqrt{6}$

$x + 1 \div x = 10$

$x + 1 \div x - 2 = 8 \\ \\ ( \sqrt{x} - 1 \div \sqrt{x} ) {}^{2} = 8$

√x-1/√x = 8^1/2

answer is

$8 {}^{1 \div 2}$

Answer 2

PLEASE ROTATE THE IMAGE UPSIDE DOWN ^^"

WELL GETTING ON TO YOUR QUESTION FIRSTLY WE NEED TO FIND THE VALUE OF X AND THEN THE VALUE OF ROOT X AND WHILE FINDING THE VALUE OF ROOT X WE WILL USE THE FORMULA

(a-b)^2.

THEN WE WILL SUBSTITUTE THE VALUES AND SOLVE IT:)