Question

0s 1. A man has to go 50 m due north, 40 m due east and
20 m due south to reach a field. (a) What distance he
has to walk to reach the field ? (b) What is his
displacement from his house to the field?
atonta from the origin goes along the X-axis
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Answer 1

Answer:

a) Distance travelled = 50 + 40 + 20 = 110 m

b) AF = AB – BF = AB – DC = 50 – 20 = 30 M

His displacement is AD AD = √ (AF2 -DF2) = √ (302 - 402) = 50m

In ΔAED tanθ = DE/AE = 30/40 = 3/4 θ = tan–1 (3/4) His displacement from his house to the field is 50 m, tan–1 (3/4) north to east

i hope it helps