Question

1 .0

1g calcium carbonate in heating will gives CO2 at STP=...........cm cube​

Answer 1

CaCO3-> CaO +CO2

molar mass of calcium carbonate = 40+12+48 = 100 g

Mole = 1/100

1 mole gives 1 mole CO2

1/100 mole gives 1 /100 mole CO2

Mole = Volume/22.4

22.4/100 = Volume