Question

1. 0.2 A current flows through a resistor of resistance 100ome for two minutes

a) calculate the heat generated ​

Answer 1

Answer:

Given :

▪ Current flow = 0.2A

▪ Resistance of conductor = 200Ω

▪ Time interval = 5min

To Find :

▪ Heat developed by conductor in the given interval of time.

Formula :

↗ Formula of heat developed by conductor in terms of current flow, resistance of conductor and time is given by

\bigstar\bf\:H=I^2Rt★H=I

2

Rt

H denotes heat energy

I denotes current

R denotes resistance

t denotes time

Conversion :

❇ 1min = 60s

❇ 5min = 5×60 = 300s

Calculation :

\begin{gathered}\implies\sf\:H=I^2Rt\\ \\ \implies\sf\:H=(0.2)^2\times 200\times 300\\ \\ \implies\sf\:H=\dfrac{240000}{100}\\ \\ \implies\underline{\boxed{\bf{H=2400J=2.4kJ}}}\:\bigstar\end{gathered}

⟹H=I

2

Rt

⟹H=(0.2)

2

×200×300

⟹H=

100

240000

⟹

H=2400J=2.4kJ

★

Answer 2

Answer:

480J

Explanation:

we know the equation,

H = I^2 Rt

H = heat generated

I= current

R = resistance

t= time

I =0.2 A

R = 100 ohm

t = 2min = 2×60 = 120 s

heat generated,

H =0.2 × 0.2 × 100 × 120

= 480 Jules