Question

(1,0) and (2,1) lie on the graph of x/a + y/b = 1 , then find the values of a and b.

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Answer 1

Let the given points be A and B.

Given Equation is (x/a) + (y/b) = 1 ------ (1)

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Given that A(1,0) lie on the given equation.

Put x = 1, y = 0 in (1), we get

= > (1/a) + (0/b) = 1

= > (1/a) = 1

= > a = 1.

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Similarly, B(2,1) lie on the given equation.

Put x = 2, y = 1 in (1), we get

= > (2/a) + (1/b) = 1

= > (2/1) + (1/b) = 1

= > 2 + (1/b) = 1

= > (1/b) = 1 - 2

= > (1/b) = -1

= > b = -1

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Therefore, the value of a = 1 and b = - 1.

Hope this helps!

Answer 2

Answer:

a=1;b=-1

Step-by-step explanation:

Let the given points be A and B.

Given Equation is (x/a) + (y/b) = 1 ------ (1)

---------------------------------------------------------------------------------------------------------------

Given that A(1,0) lie on the given equation.

Put x = 1, y = 0 in (1), we get

= > (1/a) + (0/b) = 1

= > (1/a) = 1

= > a = 1.

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Similarly, B(2,1) lie on the given equation.

Put x = 2, y = 1 in (1), we get

= > (2/a) + (1/b) = 1

= > (2/1) + (1/b) = 1

= > 2 + (1/b) = 1

= > (1/b) = 1 - 2

= > (1/b) = -1

= > b = -1

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Therefore, the value of a = 1 and b = - 1.

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