Question

. 1.0 g of CaCO3 is reacted with 0.015 mol of HCl: CaCO3 + 2HCl CaCl2 + H2O + CO2
a) Determine which reagent is present in excess.
b) Calculate the mass of CO2. ( Ar: Ca= 40, C= 12, O= 16)

Answer 1

Answer:

The answer is

Cao 3 - cl3 - 12 = 89

b) CO2

Answer 2

Answer:

Explanation:idk