Question

1.0 g of CaCO3 was dissolved in HCl and diluted to IL 50 ml of this standard hand water
requires 48 ml of EDTA while 50 ml of luard water sample requires 10 ml of EDTA solution
Calculate total temporary and permanent hardness of water​

Answer 1

Answer:

104.17

Explanation:

Concentration of S.H.W. =0.5  gm   CaCO3/500mlD.W.=500 mgs  in  500  ml  water=1mg/ml

50 ml SHW required = 48 ml of EDTA solution

∴ 1 ml EDTA solution = 50/48 mgs CaCO3 equivalent hardness.

50 ml water sample = 15 ml EDTA solution.

∴ hardness of sample = (15 * 50/48) mgs CaCO3 equivalents for 50 ml sample.

Hardness per litre of sample = (15 * 50/48)* 1000/50 mgs/lit.

Total hardness = 312.50 ppm

50 ml water sample after boiling = 10 ml EDTA solution

Permanent hardness of sample = 10 * 50/48 mgs CaCO3 equivalent for 50 ml.

Permanent hardness of one litre sample = (10 * 50/48)*1000/50 mgs/lit.

Permanent hardness of sample = 208.33 ppm

Temporary hardness = total hardness – permanent hardness= 312.5 – 208.33 = 104.17

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