1.0 g of magnesium is burnt with 0.56 g O₂ in a closed vessel. Which reactant is left in excess and how much? (At wt. Mg = 24; O = 16)
(A) Mg, 0.16 g
(B) O₂, 0.16 g
(C) Mg, 0.44 g
(D) O₂, 0.28 g
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Initially Mg +1/2 O₂→MgO (or)
1/24 mole 0.56/32 mole
0.0416 mole 0.0175 mole
(0.0416-2 ×0.0175) (2 ×0.0175) mole
=0.0066 mole
mass of Mg=0.0066 ×24
=0.158 ≈ 0.16g
good evening______________✌️✌️✌️✌️
Initially Mg +1/2 O₂→MgO (or)
1/24 mole 0.56/32 mole
0.0416 mole 0.0175 mole
(0.0416-2 ×0.0175) (2 ×0.0175) mole
=0.0066 mole
mass of Mg=0.0066 ×24
=0.158 ≈ 0.16g
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