1.0 kg weight is suspended from a wire 10 m long & cross section area 2 mm2. If the strain be 0.001 % find the elongation of the wire & also calculate stress in the wire
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Answer:
4.9×1011N/m2
Given, Length of wire (L)=10 m cross sect ion (A)=2 mm2=2×10-6 m2 Loa d (m)=1 kg So, Force =mg=1×10=10 N00
and LAL×100=0.001(AL-elongation )LAL=
1x10-5
we know, young's modulus = strain Stre
SS
=(LAL)(AF)=1×10-52-10-610
Y=4.9×1011 N/m2
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