1.0 kg weight is suspended from a wire 10 metre long and cross section area 2 mm2 . If the strain be 0.001%, find the elongation of the wire. Also calculate the stress in the wire.
Pls provide step-by-step process of calculation.
Answers
Answered by
0
Answer:
4.9×1011N/m2
Given, Length of wire (L)=10 m cross section (A)=2 mm2=2×10−6 m2 Loa d (m)=1 kg So, Force =mg=1×10=10 N00
and LΔL×100=0.001(ΔL=elongation )LΔL=1×10−5
we know, young’s modulus = strain Stress
=(LΔL)(AF)=1×10−52×10−610
Y=4.9×1011 N/m2
Answered by
0
Correct option is
B
4.9×10
11
N/m
2
Given,
Length of wire (L)=10 m
cross section (A)=2 mm
2
=2×10
−6
m
2
Loa d (m)=1 kg
So, Force =mg
=1×10
=10 N
00
and
L
ΔL
×100=0.001(ΔL=elongation )
L
ΔL
=1×10
−5
we know,
young’s modulus =
strain
Stress
=
(
L
ΔL
)
(
A
F
)
=
1×10
−5
2×10
−6
10
Y=4.9×10
11
N/m
2
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