Math, asked by raheemun8, 2 months ago

1-01
find derivative of the following
(1) y=x²+4x
(2) f(x) = sinx-3C0SX + Tanx
(3) y = 4 +3x power 10-x power 100
(4) y = 3 log x- 2rootx -5 power x


Answers

Answered by ksonakshi70
2

Answer:

1. \: y =  {x}^{2}  + 4x \\  \frac{dy}{dx}  = 2x + 4 \\ 2. \: f(x )\:  =  \sin(x) - 3 \cos(x )+  \tan(x)  \\  \frac{dy}{dx}  =  \cos(x)   + 3 \sin(x)  +  { \sec(x) }^{2}  \\ 3. \: y = 4 +  {3x}^{10}  -  {x}^{100}  \\  \frac{dy}{dx}  = 30 {x}^{9}  - 100 {x}^{99}  \\ 4. \: y = 3 log(x)  - 2 \sqrt{x}  -  {5}^{x}  \\  \frac{dy}{dx}  =  \frac{3}{x}  -  \frac{1}{ \sqrt{x} }  - 5  {}^{x} log(5)

Answered by akash1999tripathi
2

Answer:

1)- 2x+4

2)- 1+3sinx+sec^2x

3)-30x^9-100x^99

4)- 3rootx -2x/xrootx

Step-by-step explanation:

1) y=x^24x

=d/dx .x^2+d/dx .4x

=2x+4

2)d/dx .x-d/dx.3xcosx+d/dx.tanx

=1+3sinx+0+sec^2x

=1+3sinx+sec^2x.

3) =d/dx.4+d/dx3x^10-d/dx.x^100

=30x^9-100x^99

4)d/dx.3logx -d/dx2x^1/2-d/dx5^x

=3×1/x-2/rootx-0

=3/x-2/rootx

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