1.03g of mixture of sodium carbonate and calcium carbonate require 20ml N HCl for complete neutralisation. calculate the percentage of sodium carbonate and calcium carbonate in the given mixture.
Answers
Calcium carbonate reacts with hydrochloric acid and produces carbon dioxide, as shown in the following equation:
CaCO3(s)+2HCl(aq)⟶Ca2+(aq)+2Cl−(aq)+H2O(l)+CO2(g)(1)(1)CaCO3(s)+2HCl(aq)⟶Ca2+(aq)+2Cl−(aq)+H2O(l)+CO2(g)
which can be simplified as:
CO2−3(aq)+2H+(aq)⟶H2O(l)+CO2(g)(2)(2)CO32−(aq)+2H+(aq)⟶H2O(l)+CO2(g)
By reacting the antacid with excess acid and then collecting the carbon dioxide produced in a constant predetermined volume, we will be able to use the ideal gas law and the molecular weight of calcium carbonate (100.0869 g/mol) to determine the weight percent of calcium carbonate in the antacid tablet.
PV=nRT(Ideal Gas Law)
The pressure of the flask will be monitored with a pressure sensor and temperature will be monitored using a temperature probe, both connected to a Verniercomputer interface unit. Using the ideal gas law and a known standard sample of calcium carbonate you will determine the volume of the flask