Question

1.04^2-0.96^2 using identities

Answer 1

We have to use the identity
a^2-b^2 = (a+b)(a-b)
so,
(1.04^2)-(0.96^2)
= (1.04+0.96)(1.04-0.96)
= 2.00×0.08
= 0.16