1.05*9.5 using identity evaluate
HappiestWriter012:
very good question
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Answered by
6
1.05×9.5
1.05 × 0.95 × 10
(1 + 0.05)× (1− 0.05) × 10
[(1)² − (0.05)²] × 10
[1 − 0.0025] × 10
0.9975 × 10
9.975
1.05 × 0.95 × 10
(1 + 0.05)× (1− 0.05) × 10
[(1)² − (0.05)²] × 10
[1 − 0.0025] × 10
0.9975 × 10
9.975
Answered by
5
1.05 *9.5
{105*95}/1000
{(100+5)(100-5)}/1000
{100²-5²}/1000
{10000-25}/1000
9975/1000
9.975
[a+c][a-c]=a²-c²
please mark it as brainliest
{105*95}/1000
{(100+5)(100-5)}/1000
{100²-5²}/1000
{10000-25}/1000
9975/1000
9.975
[a+c][a-c]=a²-c²
please mark it as brainliest
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