1.06g of sodium carbonate is dissolved in 200ml of water. calculate morality?
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Answer:
your answer is
The dissociation equilibrium is Na2CO3⇋2Na++CO32−.
The molar concentration of sodium carbonate is 106 g/mol1.06 g×250 mL1000 mL×1 L=0.04 M.
This is also equal to the molar concentration of carbonate ion.
The molar concentration of sodium ion is equal to 2×0.04 M=0.08 M=8×10−2M.
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Answered by
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The dissociation equilibrium is Na
2
CO
3
⇋2Na
+
+CO
3
2−
.
The molar concentration of sodium carbonate is
106 g/mol
1.06 g
×
250 mL
1000 mL
×1 L=0.04 M.
This is also equal to the molar concentration of carbonate ion.
The molar concentration of sodium ion is equal to 2×0.04 M=0.08 M=8×10
−2
M.
2
CO
3
⇋2Na
+
+CO
3
2−
.
The molar concentration of sodium carbonate is
106 g/mol
1.06 g
×
250 mL
1000 mL
×1 L=0.04 M.
This is also equal to the molar concentration of carbonate ion.
The molar concentration of sodium ion is equal to 2×0.04 M=0.08 M=8×10
−2
M.
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