1.08 g of a metal oxide on being reduced gives 1 g of metal. Calculate the eq. weight of the metal.
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here we use the concept that equivalents of metal oxide = equivalents of metal
eq.of metal oxide=1.08/(E+8) where E=eq. weight of METAL // note eq. weight of oxygen in metal oxide is 8
eq. of metal=1/E
now equating these we get
1.08/(E+8)=1/E which gives E=100 HENCE THE ANS.....
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