1.0g of magnesium is burnt with 0.56g O2(oxygen) in a closed vessel . Which reactant is left in excess and how much ? (At. wt. Mg = 24 ; O = 16)
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Answered by
93
2Mg+O2-------> 2MgO
here we look 32 g of O2 is react with 48g of Mg
so ,1 g of O2 is react with 48/32g=3/2g of Mg
so, 0.56 g of O2 is react with 0.84g of Mg
hence Mg is that reagent which is excess and (1-0.84)=0.16g excess
here we look 32 g of O2 is react with 48g of Mg
so ,1 g of O2 is react with 48/32g=3/2g of Mg
so, 0.56 g of O2 is react with 0.84g of Mg
hence Mg is that reagent which is excess and (1-0.84)=0.16g excess
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10
Answer:
Explanation:2Mg+O2-------> 2MgO
here we look 32 g of O2 is react with 48g of Mg
so ,1 g of O2 is react with 48/32g=3/2g of Mg
so, 0.56 g of O2 is react with 0.84g of Mg
hence Mg is that reagent which is excess and (1-0.84)=0.16g
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