Question

1.0gram of a mixture of chalk and slaked lime requires 22.81ml of (N)HCL to dissolve it how much of each is present in the mixture​

Answer 1

Answer:

let the mass of chalk be x gm then mass of slaked lime will be 1-x gm

now number of moles of hcl will be equal to moles to chalk and slaked lime .

so we can write an equation =

x/100+(1-x)/74=22.81/36.5

solve it and get the answer ..